Integrand size = 22, antiderivative size = 116 \[ \int \frac {x^5}{\sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=-\frac {3}{4} \left (1-x^2\right )^{2/3}-\frac {9 \left (1-x^2\right )^{2/3}}{8 \left (3+x^2\right )}-\frac {21 \sqrt {3} \arctan \left (\frac {1+\sqrt [3]{2-2 x^2}}{\sqrt {3}}\right )}{8\ 2^{2/3}}+\frac {21 \log \left (3+x^2\right )}{16\ 2^{2/3}}-\frac {63 \log \left (2^{2/3}-\sqrt [3]{1-x^2}\right )}{16\ 2^{2/3}} \]
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Time = 0.06 (sec) , antiderivative size = 116, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.318, Rules used = {457, 91, 81, 57, 631, 210, 31} \[ \int \frac {x^5}{\sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=-\frac {21 \sqrt {3} \arctan \left (\frac {\sqrt [3]{2-2 x^2}+1}{\sqrt {3}}\right )}{8\ 2^{2/3}}-\frac {3}{4} \left (1-x^2\right )^{2/3}-\frac {9 \left (1-x^2\right )^{2/3}}{8 \left (x^2+3\right )}+\frac {21 \log \left (x^2+3\right )}{16\ 2^{2/3}}-\frac {63 \log \left (2^{2/3}-\sqrt [3]{1-x^2}\right )}{16\ 2^{2/3}} \]
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Rule 31
Rule 57
Rule 81
Rule 91
Rule 210
Rule 457
Rule 631
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {x^2}{\sqrt [3]{1-x} (3+x)^2} \, dx,x,x^2\right ) \\ & = -\frac {9 \left (1-x^2\right )^{2/3}}{8 \left (3+x^2\right )}+\frac {1}{8} \text {Subst}\left (\int \frac {-9+4 x}{\sqrt [3]{1-x} (3+x)} \, dx,x,x^2\right ) \\ & = -\frac {3}{4} \left (1-x^2\right )^{2/3}-\frac {9 \left (1-x^2\right )^{2/3}}{8 \left (3+x^2\right )}-\frac {21}{8} \text {Subst}\left (\int \frac {1}{\sqrt [3]{1-x} (3+x)} \, dx,x,x^2\right ) \\ & = -\frac {3}{4} \left (1-x^2\right )^{2/3}-\frac {9 \left (1-x^2\right )^{2/3}}{8 \left (3+x^2\right )}+\frac {21 \log \left (3+x^2\right )}{16\ 2^{2/3}}-\frac {63}{16} \text {Subst}\left (\int \frac {1}{2 \sqrt [3]{2}+2^{2/3} x+x^2} \, dx,x,\sqrt [3]{1-x^2}\right )+\frac {63 \text {Subst}\left (\int \frac {1}{2^{2/3}-x} \, dx,x,\sqrt [3]{1-x^2}\right )}{16\ 2^{2/3}} \\ & = -\frac {3}{4} \left (1-x^2\right )^{2/3}-\frac {9 \left (1-x^2\right )^{2/3}}{8 \left (3+x^2\right )}+\frac {21 \log \left (3+x^2\right )}{16\ 2^{2/3}}-\frac {63 \log \left (2^{2/3}-\sqrt [3]{1-x^2}\right )}{16\ 2^{2/3}}+\frac {63 \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+\sqrt [3]{2-2 x^2}\right )}{8\ 2^{2/3}} \\ & = -\frac {3}{4} \left (1-x^2\right )^{2/3}-\frac {9 \left (1-x^2\right )^{2/3}}{8 \left (3+x^2\right )}-\frac {21 \sqrt {3} \tan ^{-1}\left (\frac {1+\sqrt [3]{2-2 x^2}}{\sqrt {3}}\right )}{8\ 2^{2/3}}+\frac {21 \log \left (3+x^2\right )}{16\ 2^{2/3}}-\frac {63 \log \left (2^{2/3}-\sqrt [3]{1-x^2}\right )}{16\ 2^{2/3}} \\ \end{align*}
Time = 0.25 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.03 \[ \int \frac {x^5}{\sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=\frac {3}{32} \left (-\frac {4 \left (1-x^2\right )^{2/3} \left (9+2 x^2\right )}{3+x^2}-14 \sqrt [3]{2} \sqrt {3} \arctan \left (\frac {1+\sqrt [3]{2-2 x^2}}{\sqrt {3}}\right )-14 \sqrt [3]{2} \log \left (-2+\sqrt [3]{2-2 x^2}\right )+7 \sqrt [3]{2} \log \left (4+2 \sqrt [3]{2-2 x^2}+\left (2-2 x^2\right )^{2/3}\right )\right ) \]
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Time = 8.04 (sec) , antiderivative size = 114, normalized size of antiderivative = 0.98
method | result | size |
pseudoelliptic | \(\frac {21 \left (x^{2}+3\right ) \left (-2 \sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (1+2^{\frac {1}{3}} \left (-x^{2}+1\right )^{\frac {1}{3}}\right )}{3}\right )+\ln \left (\left (-x^{2}+1\right )^{\frac {2}{3}}+2^{\frac {2}{3}} \left (-x^{2}+1\right )^{\frac {1}{3}}+2 \,2^{\frac {1}{3}}\right )-2 \ln \left (\left (-x^{2}+1\right )^{\frac {1}{3}}-2^{\frac {2}{3}}\right )\right ) 2^{\frac {1}{3}}-12 \left (-x^{2}+1\right )^{\frac {2}{3}} \left (2 x^{2}+9\right )}{32 x^{2}+96}\) | \(114\) |
trager | \(\text {Expression too large to display}\) | \(656\) |
risch | \(\text {Expression too large to display}\) | \(662\) |
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Time = 0.27 (sec) , antiderivative size = 153, normalized size of antiderivative = 1.32 \[ \int \frac {x^5}{\sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=-\frac {3 \, {\left (28 \cdot 4^{\frac {1}{6}} \sqrt {3} \left (-1\right )^{\frac {1}{3}} {\left (x^{2} + 3\right )} \arctan \left (\frac {1}{6} \cdot 4^{\frac {1}{6}} \sqrt {3} {\left (2 \, \left (-1\right )^{\frac {1}{3}} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} - 4^{\frac {1}{3}}\right )}\right ) + 7 \cdot 4^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} {\left (x^{2} + 3\right )} \log \left (4^{\frac {1}{3}} \left (-1\right )^{\frac {2}{3}} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} - 4^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} + {\left (-x^{2} + 1\right )}^{\frac {2}{3}}\right ) - 14 \cdot 4^{\frac {2}{3}} \left (-1\right )^{\frac {1}{3}} {\left (x^{2} + 3\right )} \log \left (-4^{\frac {1}{3}} \left (-1\right )^{\frac {2}{3}} + {\left (-x^{2} + 1\right )}^{\frac {1}{3}}\right ) + 8 \, {\left (2 \, x^{2} + 9\right )} {\left (-x^{2} + 1\right )}^{\frac {2}{3}}\right )}}{64 \, {\left (x^{2} + 3\right )}} \]
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\[ \int \frac {x^5}{\sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=\int \frac {x^{5}}{\sqrt [3]{- \left (x - 1\right ) \left (x + 1\right )} \left (x^{2} + 3\right )^{2}}\, dx \]
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Time = 0.29 (sec) , antiderivative size = 115, normalized size of antiderivative = 0.99 \[ \int \frac {x^5}{\sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=-\frac {21}{32} \cdot 4^{\frac {2}{3}} \sqrt {3} \arctan \left (\frac {1}{12} \cdot 4^{\frac {2}{3}} \sqrt {3} {\left (4^{\frac {1}{3}} + 2 \, {\left (-x^{2} + 1\right )}^{\frac {1}{3}}\right )}\right ) + \frac {21}{64} \cdot 4^{\frac {2}{3}} \log \left (4^{\frac {2}{3}} + 4^{\frac {1}{3}} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} + {\left (-x^{2} + 1\right )}^{\frac {2}{3}}\right ) - \frac {21}{32} \cdot 4^{\frac {2}{3}} \log \left (-4^{\frac {1}{3}} + {\left (-x^{2} + 1\right )}^{\frac {1}{3}}\right ) - \frac {3}{4} \, {\left (-x^{2} + 1\right )}^{\frac {2}{3}} - \frac {9 \, {\left (-x^{2} + 1\right )}^{\frac {2}{3}}}{8 \, {\left (x^{2} + 3\right )}} \]
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Time = 0.32 (sec) , antiderivative size = 115, normalized size of antiderivative = 0.99 \[ \int \frac {x^5}{\sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=-\frac {21}{32} \cdot 4^{\frac {2}{3}} \sqrt {3} \arctan \left (\frac {1}{12} \cdot 4^{\frac {2}{3}} \sqrt {3} {\left (4^{\frac {1}{3}} + 2 \, {\left (-x^{2} + 1\right )}^{\frac {1}{3}}\right )}\right ) + \frac {21}{64} \cdot 4^{\frac {2}{3}} \log \left (4^{\frac {2}{3}} + 4^{\frac {1}{3}} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} + {\left (-x^{2} + 1\right )}^{\frac {2}{3}}\right ) - \frac {21}{32} \cdot 4^{\frac {2}{3}} \log \left (4^{\frac {1}{3}} - {\left (-x^{2} + 1\right )}^{\frac {1}{3}}\right ) - \frac {3}{4} \, {\left (-x^{2} + 1\right )}^{\frac {2}{3}} - \frac {9 \, {\left (-x^{2} + 1\right )}^{\frac {2}{3}}}{8 \, {\left (x^{2} + 3\right )}} \]
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Time = 5.30 (sec) , antiderivative size = 137, normalized size of antiderivative = 1.18 \[ \int \frac {x^5}{\sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx=-\frac {21\,2^{1/3}\,\ln \left (\frac {3969\,{\left (1-x^2\right )}^{1/3}}{64}-\frac {3969\,2^{2/3}}{64}\right )}{16}-\frac {9\,{\left (1-x^2\right )}^{2/3}}{8\,\left (x^2+3\right )}-\frac {3\,{\left (1-x^2\right )}^{2/3}}{4}-\frac {21\,2^{1/3}\,\ln \left (\frac {3969\,{\left (1-x^2\right )}^{1/3}}{64}-\frac {3969\,2^{2/3}\,{\left (-1+\sqrt {3}\,1{}\mathrm {i}\right )}^2}{256}\right )\,\left (-1+\sqrt {3}\,1{}\mathrm {i}\right )}{32}+\frac {21\,2^{1/3}\,\ln \left (\frac {3969\,{\left (1-x^2\right )}^{1/3}}{64}-\frac {3969\,2^{2/3}\,{\left (1+\sqrt {3}\,1{}\mathrm {i}\right )}^2}{256}\right )\,\left (1+\sqrt {3}\,1{}\mathrm {i}\right )}{32} \]
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